ΔTb = i x Kb x molality, where i is Van't Hoff factor
Given, ΔTb = 1.88 K
Kb = 0.52 K kg mol-1
Molality = 2
i = \(\frac{1.88}{0.52\times2}\)
i = 1.8076
This value of ‘i’ signifies that when 1 mole of NaCl is dissolved in water it dissociates to give 1.8076 moles of particles in the solution.