(i) Two lines intersects each other
∴ ∠x = ∠55°, (Vertically opposite angles)
∴ x + z = 180° (Linear pair angle)
⇒ 55° + ∠z = 180°
⇒ ∠z = 180°- 55° = 125°
Clearly ∠z = ∠y, (Vertically opposite angles)
⇒ ∠y = 125°
∠x = 55°, ∠y = 125°
and ∠z = 125°.
(ii) 40° + ∠x + 25° = 180° (Straight angle)
⇒ 65 + ∠x = 180°
⇒ ∠x = 180° – 65° = 115°
and ∠y + 40° = 180°, (Linear pair angle)
⇒ ∠y= 180° – 40° = 140°
and ∠y + ∠z = = 180°, (Linear pair angle)
∠z = 180°- ∠y
= 180°- 140° = 40°
∴ ∠x = 115°, ∠y = 140° and ∠z = 40°