∠e + 125° = 180°, (Linear pair angle)
⇒ ∠e = 180° – 125° = 55°,
∠e = ∠f = 55°, (Vertically opposite angles)
In figure, p ॥ q and t is a transversal
∠a = ∠f, (Alternate angle)
∠a = 55°, (∵ ∠f = 55°)
∠d = 125°, (Corresponding angels)
∠c = ∠a = 55°, (Vertically opposite angles)
and ∠b = ∠d = 125°, (Vertically opposite angles)
Thus, ∠a = 55°, ∠b = 125°, ∠c = 55°, ∠d = 125°, ∠e = 55° and ∠f= 55°