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in Congruence of Triangles by (50.4k points)
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In figure AB = AC and D is mid point of BC.

(i) Write three pairs of equal parts in ∆ADB and ∆ACD.

(ii) Is ∆ADB = ∆ADC ?

Give reason.

(iii) What is relation between ∠B and ∠C?

1 Answer

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by (48.4k points)
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Best answer

(i) In ∆ADB and ∆ADC

AD = AD (common)

AB = AC (given)

and DB = DC (∵ D is mid point of BD)

(ii) By S.S.S. rule of congruency.

∆ADB ≅ ∆ADC

(iii) ∠B = ∠C (CPCT)

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