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In ∆ABC ∠A = 50°, ∠B = 70°, then find the value of ∠C.

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In ∆ABC ∠A = 50°, ∠B = 70°, then find the value of ∠C.

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Given ∠A = 50° and ∠B = 70°

Sum of all three angles of a triangle is 180°.

∠A + ∠B + ∠C = 180°
⇒ 50° + 70° + ∠C = 180°
⇒ 120° + ∠C = 180°
⇒∠C = 180° – 120° = 60°

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