Use app×
Join Bloom Tuition
One on One Online Tuition
JEE MAIN 2025 Foundation Course
NEET 2025 Foundation Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
0 votes
7.0k views
in Physics by (47.6k points)
closed by

Calculate the work done by the brakes of a car of mass 1000kg when its speed is reduced from 20 m/s to 10 m/s.

1 Answer

+1 vote
by (46.9k points)
selected by
 
Best answer

Mass of car = 1000 kg 

Initial velocity, u = 20 m/s 

Final velocity, v = 10 m/s 

Retardation = a 

Distance covered = s 

Using third equation of motion 

v2 – u2 = 2as 

as = -150 

Work done, 

W = Fs

F = ma 

W = mas 

as = -150 

W = (1000)(150) = -150 kJ 

Negative sign shows that the brakes are acting on the opposite direction of motion.

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

Categories

...