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ABC is a right angled triangle with ∠ABC = 90°. D is any point on AB and DE is perpendicular to AC.

Prove that: 

(i) ∆ADE ~ ∆ACB. 

(ii) If AC = 13 cm, BC = 5 cm and AE – 4 cm. Find DE and AD.

(iii) Find, area of ∆ ADE: area of quadrilateral BCED.

1 Answer

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Best answer

(i) In ∆ADE and ∆ACB

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