Question

Resistance of a conductivity cell filled with 0.1 mol L^-1 KCl solution is 100 Ω. If the resistance of the same cell when filled with 0.02 mol L^-1 KCl solution is 520 Ω, calculate the conductivity and molar conductivity of 0.02 mol L^-1 KCl solution. The conductivity of 0.1 mol L^-1 KCl solution is 1.29 S/m.

Answer 1

From question, conductivity (K) = 1.29 S/m = 1.29 x 10^-2 S cm^-1
Cell constant (G*) = conductivity (K) × Resistance
= 1.29 × 10^-2 × 100 = 1.29 cm^-1
Conductivity for 0.02 M solution