Fewpal
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34.05 mL of phosphorus vapour weighs 0.0625 g at 546 °C and 0.1 bar pressure. What is the molar mass of phosphorus? 

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Given, 

p = 0.1 bar 

V = 34.05 mL = 34.05 × 10–3 L = 34.05 × 10–3 dm3 

R = 0.083 bar dm3 K –1 mol–1 

T = 546°C = (546 + 273) 

K = 819 K The number of moles (n) can be calculated using the ideal gas equation as: 

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