# Calculate the temperature of 4.0 mol of a gas occupying 5 dm3 at 3.32 bar. (R = 0.083 bar dm3 K –1 mol–1 ).

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Calculate the temperature of 4.0 mol of a gas occupying 5 dm3 at 3.32 bar. (R = 0.083 bar dm3 K –1 mol–1 ).

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Given,

Amount of the gas ,n = 4.0 mol

Volume of the gas ,V = 5 dm3

Pressure of the gas,p = 3.32 bar

R = 0.083 bar dm3 K–1 mol–1

From the ideal gas equation, we get

pV = nRT

T = pV / nR

= (3.32x5) /  (4x0.083)

= 50K

Hence, the required temperature is 50 K.

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Given,n=4.0 mol

V=5dm3

p=3.32 bar

R = 0.083 bar dm3K–1mol–1

The temperature (T) can be calculated using the ideal gas equation as:

Hence, the required temperature is 50 K.