Given,

Amount of the gas ,*n* = 4.0 mol

Volume of the gas* ,V* = 5 dm^{3}

Pressure of the gas,*p* = 3.32 bar

R = 0.083 bar dm^{3} K^{–1} mol^{–1}

From the ideal gas equation, we get

*pV = nRT*

⇒* T = pV ***/** nR

* = (3.32x5) ***/ (**4x0.083)

* = 50K*

Hence, the required temperature is 50 K.