Let the distance Vishal travelled by bus be x km and by aeroplane be y km.
According to the first condition,
x + y = 1900 …(i)
Time = \(\frac{Distance}{Speed}\)
∴ Time required to cover x km by bus = \(\frac{x}{60}\) hr
Time required to cover y km by aeroplane = \(\frac{y}{700}\) hr
According to the second condition
\(\frac{x}{60}\) + \(\frac{y}{700}\) = 5
∴ \(\frac{700x + 60 y}{60 X 700 }\) = 5
∴ 700x + 60y = 5 x 60 x 700
∴ 70x + 6y = 21000 ......(iii) [ Dividing both sides by 10 ]
Multiplying equation (i) by 6, we get
6x + 6y= 11400 …(iii)
Subtracting equation (iii) from (ii), we get
∴ x = \(\frac{9600}{64}\)
∴ x = 150
∴ The distance Vishal travelled by bus is 150 km.