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250 g of water at 30 °C is present in a copper vessel of mass 50 g. Calculate the mass of ice required to bring down the temperature of the vessel and its contents to 5 °C. 

Specific latent heat of fusion of ice = 336 x 103 J kg-1 . 

Specific heat capacity of copper vessel = 400 J kg-1 °C-1

Specific heat capacity of water = 4200 J kg-1 °C-1 .

1 Answer

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Best answer

Heat lost by ice = Heat gained by water + Heat gained by copper

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