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A bomb is dropped from an aeroplane when it is directly above a target at a height of 1254.4m. The aeroplane is going horizontally with a speed of 150m/s. The distance by which it will miss the target is

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2 Answers

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by (21.2k points)

Correct answer is 2.4 km

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How is it 2.4 km?
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by (5.0k points)

D = u√2H/g

Where D is distance, u is initial velocity, H is height and g is acceleration due to gravity.

Putting the values,

D= 150√2×1254.4/9.8

D= 150√2508.8/9.8

D= 150√256

D= 150×16

D= 2400m

D= 2.4 km

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