(i) Addition of 3 and x = x + 3 (LHS)
Real result = 11 (RHS)
Thus equation x + 3 = 11.
(ii) Subtracting 7 from x = x – 7 (LHS)
Real remainder = 12 (RHS)
Thus, equation x – 7= 12.
(iii) Increasing 10 in number = x + 10 (LHS)
Real result = 22 (RHS)
Thus, equation x + 10 = 22.
(iv) Let number is x
Five times of number = 5x (LHS)
Product = 35 (RHS)
Thus, equation 5x = 35.
(v) Let x subtracted from 15 then
Remainder = 15 – x (LHS)
Real remainder = 2 (RHS)
Thus, equation 15 – x = 2