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in Algebra by (48.7k points)
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Convert following open statement into equations 

(i) While adding 3 in x, gives 11. 

(ii) On subtraction x form 7, 12 remains. 

(iii) Increasing a number by 10, we get 22. 

(iv) 5 times of a number is 35. 

(v) How much subtract from 15, to get 2 ?

1 Answer

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Best answer

(i) Addition of 3 and x = x + 3 (LHS) 

Real result = 11 (RHS) 

Thus equation x + 3 = 11. 

(ii) Subtracting 7 from x = x – 7 (LHS) 

Real remainder = 12 (RHS) 

Thus, equation x – 7= 12. 

(iii) Increasing 10 in number = x + 10 (LHS)

Real result = 22 (RHS) 

Thus, equation x + 10 = 22. 

(iv) Let number is x 

Five times of number = 5x (LHS) 

Product = 35 (RHS) 

Thus, equation 5x = 35. 

(v) Let x subtracted from 15 then 

Remainder = 15 – x (LHS) 

Real remainder = 2 (RHS) 

Thus, equation 15 – x = 2

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