(i) (let) Side of square = a
Then, Area = a × a = a2
If length of side = (1/2) × a = a/2
Then Area = a/2 a/2 = a2/4
= (1/4)a2 = 1/4 = (initial area)
Thus, New area, remains one fourth of initial area.
(ii) Side of square (let) = a
Then area = a × a = a2 if length doubled, then side = 2a and
Area = 2a × 2a = 4a2
= 4(a2) = 4 (initial area)
Thus, New area, became four times of initial area.