Emp. formula = X2Y, At. wt. of X = 10, At .wt. of of Y = 5
∴ Empirical formula mass = 2 x 10 + 5 = 25
If Vapour density V.D = 25
Mol.Mass = V.D. x 2 = 25 x 2 = 50 u
n = \(\frac{Mol.\,Mass}{Emp.\,formula\,mass}\) = \(\frac{50}{25}\) = 2
Mol. formula = Emp. formula x 2 = X2Y x 2
= X4Y2