Fewpal
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∆Uθof combustion of methane is – X kJ mol–1 . The value of ∆Hθ is

(i) = ∆Uθ

(ii) > ∆Uθ

(iii) < ∆Uθ

(iv) = 0

1 Answer

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Best answer

Since ∆Hθ = ∆Uθ + ∆ngRT and ∆Uθ = –X kJ mol–1

∆Hθ = (–X) + ∆ngRT. ⇒ ∆Hθ < ∆Uθ 

Therefore, alternative (iii) is correct. 

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