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Find the total percentage of Magnesium in magnesium nitrate crystals, Mg(NO3)2.6H2O. [Mg = 24; N = 14; 0 = 16 and H = 1]

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Best answer

Mg(NO3)2.6H2O

24 + 14 x 2 + 16 x 6 + 6 x 18 = 256 gm.

% of Mg = \(\frac{24}{256}\times100\) 

= 9.375 %

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