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Calculate the standard enthalpy of formation of CH3OH(l) from the following data: 

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The reaction that takes place during the formation of CH3OH(l) can be written as: 

C(s) + 2H2O(g) +           CH3OH(l) (1) 

The reaction (1) can be obtained from the given reactions by following the algebraic calculations as: 

Equation (ii) + 2 × equation (iii) – equation (i) 

fHθ [CH3OH(l)] = ∆cHθ + 2∆fHθ [H2O(l)] – ∆rHθ 

= (–393 kJ mol–1 ) + 2(–286 kJ mol–1 ) – (–726 kJ mol–1

= (–393 – 572 + 726) kJ mol–1 

fHθ [CH3OH(l)] = –239 kJ mol–1  

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