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Calculate the enthalpy change for the process 

CCl4(g) → C(g) + 4Cl(g) and calculate bond 

enthalpy of C–Cl in CCl4(g)

vapHθ (CCl4) = 30.5 kJ mol–1

fHθ (CCl4) = –135.5 kJ mol–1

aHθ (C) = 715.0 kJ mol–1 , where ∆aHθ is enthalpy of atomisation 

aHθ (Cl2) = 242 kJ mol–1

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The chemical equations implying to the given values of enthalpies are: 

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