Question

From the equation

C + 2H₂SO₄ → CO₂ + 2H₂O + 2SO₂ 

Calculate: 

(i) The mass of carbon oxidized by 49 g of sulphuric acid (C = 12; relative molecular mass of sulphuric acid = 98).

(ii) The volume of sulphur dioxide measured at stp. liberated at the same time. (Volume occupied by 1 mole of a gas at stp is 22.4 dm³ )

Answer 1

(i) From equation:

2 x 98 g of sulphuric acid oxidises 12g of carbon

∴  49 g of sulphuric acid will oxidise = \(\frac{12\times49}{2\times98}\)

                                                     = 3g of C.

(ii) From equation:

2 x 98 of sulphuric acid liberates 2 x 22.4 l of SO₂.

  49 g of sulphuric acid will liberate = \(\frac{2\times22.4\times49}{2\times98}\)

                                               = 11.2 l of SO₂.