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Solve the following sets of simultaneous equations. 

i. x + y = 4 ; 2x – 5y = 1 

ii. 2x + y = 5 ; 3x – y = 5 

iii. 3x – 5y = 16; x – 3y= 8 

iv. 2y – x = 0; 10x + 15y = 105 

v. 2x + 3y + 4 = 0; x – 5y = 11 

vi. 2x – 7y = 7; 3x + y = 22

1 Answer

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i. Substitution Method:

x + y = 4 

∴ x = 4 – y …(i) 

2x – 5y = 1 ……(ii) 

Substituting x = 4 – y in equation (ii), 

2(4 – y) – 5y = 1 

∴ 8 – 2y – 5y = 1 

∴ 8 – 7y = 1 

∴ 8 – 1 = 7y 

∴ 7 = 7y 

∴ y = 7/7

∴ y = 1 

Substituting y = 1 in equation (i), 

x = 4 – 1 = 3 

∴ (3,1) is the solution of the given equations. 

Alternate method: 

Elimination Method: 

x + y = 4 …(i) 

2x – 5y = 1 ……(ii)

Multiplying equation (i) by 5, 

5x + 5y = 20 … (iii) 

Adding equations (ii) and (iii), 

2x – 5y = 1 + 5x + 5y = 20 

7 = 21 

∴ x = 21/7

∴ x = 3 

Substituting x = 3 in equation (i), 

3 + y = 4 

∴ y = 4 – 3 = 1 

(3,1) is the solution of the given equations.

ii. 2x + y = 5 …(i) 

3x – y = 5 …(ii) 

Adding equations (i) and (ii), 

2x + y = 5 + 3x – y = 5 

5x = 10

∴ x = 10/5

∴ x = 2 

Substituting x = 2 in equation (i), 

2(2) + y = 5 

4 + y = 5 

∴ y = 5 – 4 = 1 

∴ (2, 1) is the solution of the given equations. 

iii. 3x – 5y = 16 …(i) 

x – 3y = 8 

∴ x = 8 + 3y …..(ii) 

Substituting x = 8 + 3y in equation (i), 

3(8 + 3y) – 5y = 16 

24 + 9y- 5y = 16 

∴ 4y= 16 – 24 

∴ 4y = -8

∴ y = -8/4

y = -2 

Substituting y = -2 in equation (ii),

x = 8 + 3 (-2) 

∴ x = 8 – 6 = 2 

∴ (2, -2) is the solution of the given equations.

iv. 2y – x = 0 

∴ x = 2y …(i) 

10x + 15y = 105 …(ii) 

Substituting x = 2y in equation (ii), 

10(2y) + 15y = 105 

∴ 20y + 15y = 105 

∴ 35y = 105 

∴ y = 105/35

∴ y = 3 Substituting y = 3 in equation (i), 

x = 2y 

∴ x = 2(3) = 6 

∴ (6, 3) is the solution of the given equations.

v. 2x + 3y + 4 = 0 …(i) 

x – 5y = 11 

∴ x = 11 + 5y …(ii) 

Substituting x = 11 + 5y in equation (i), 

2(11 +5y) + 3y + 4 = 0 

∴ 22 + 10y + 3y + 4 = 0 

∴ 13y + 26 = 0 

∴ 13y = -26 

∴ y = -26/13

∴ y = -2 

Substituting y = -2 in equation (ii), 

x = 11 + 5y 

∴ x = 11 + 5(-2) 

∴ x = 11 – 10 = 1 

∴ (1, -2) is the solution of the given equations. 

vi. 2x – 7y = 7 …(i) 

3x + y = 22

∴ y = 22 – 3x ……(ii)

Substituting y = 22 – 3x in equation (i), 

2x – 7(22 – 3x) = 7 

∴ 2x – 154 + 21x = 7 

∴ 23x = 7 + 154 

∴ 23x = 161 

∴ x = 161/23 

∴ x = 7 

Substituting x = 7 in equation (ii), 

y = 22 – 3x 

∴ y = 22 – 3(7) 

∴ 7 = 22 - 21= 1 

∴ (7, 1) is the solution of the given equations.

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