Factors of 3600 = 2 × 2 × 2 × 2 × 3 × 3 × 5 × 5
Now, grouping the prime factors = (2 × 2 × 2) × 2 × 3 × 3 × 5 × 5
Factors 2, 3 and 5 has no pair.
∴3600 is not a perfect cube.
The smallest number it should be multiplied to get a perfect cube is 2 × 2 × 3 × 5 = 60
Then,
Product = 3600 × 60 = 216000
Factors of 21600 = 2 × 2 × 2 × 2 × 2 × 2 × 3 × 3 × 3 × 5 × 5 × 5
= 3√216000
= 3√(23 × 23 × 33 × 53)
= 2 × 2 × 3 × 5
= 60