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0 votes
7.2k views
in Linear Equations by (50.4k points)
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The digit in the tens place of a two digit number is 3 more than the digit in the units place. Let the digit at units place be b. Then the number is

(a) 11b + 30 (b) 10b + 30 (c) 11b + 3 (d) 10b + 3

1 Answer

+1 vote
by (49.8k points)
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Best answer

(a) 11b + 30

From the question it is given that,

Let the digit at units place be b.

The digit in the tens place of a two digit number is 3 more than the digit in the units place = 3 + b

So, the number = 10 (3 + b) + b

= 30 + 10b + b

= 30 + 11b

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