We have,
[(y – (4 – 3y))/ (2y – (3 + 4y))] = 1/5
(y – 4 + 3y)/ (2y – 3 – 4y) = 1/5
(-4y – 4)/ (2y – 3) = 1/5
By cross multiplication, we get
5 × (-4y – 4) = 1 × (2y – 3)
20y – 20 = 2y – 3
Transposing – 20 to RHS it becomes 20 and 6y to LHS it becomes -6y.
20y – 2y = 20 – 3
22 y = 17
y = 17/22