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In ∆PQR, ∠P = 70°, ∠Q = 65° , then find ∠R.

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In ∆PQR, ∠P = 70°, ∠Q = 65° , then find ∠R.

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∠P = 70° , ∠Q = 65° [Given] 

In ∆PQR, 

∠P + ∠Q + ∠R = 180° [Sum of the measures of the angles of a triangle is 180°] 

∴ 70° + 65° + ∠R = 180° 

∴ ∠R = 180° – 70° – 65° 

∴ ∠R = 45°

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