i. AC = 8 cm …(i) [Given]
ABCD is a rectangle [Given]
∴ BD = AC [Diagonals of a rectangle are congruent]
∴ BD = 8 cm [From (i)]
BO = (1/2) BD [Diagonals of a rectangle bisect each other]
∴ BO = (1/2) x 8
∴ BO = 4 cm
ii. side AD || side BC and seg AC is their transversal. [Opposite sides of a rectangle are parallel]
∴ ∠ACB = ∠CAD [Alternate angles]
∠ACB = 35° [ ∵∠CAD = 35°]
∴ BO = 4 cm,
∠ACB = 35°
