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Diagonals of a rectangle PQRS are intersecting in point M. If ∠QMR = 50°, then find the measure of ∠MPS.

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Best answer

PQRS is a rectangle. 

∴ PM = (1/2) PR …(i) 

MS = (1/2) QS …(ii) [Diagonals of a rectangle bisect each other] 

Also, PR = QS …..(iii) [Diagonals of a rectangle are congruent] 

∴ PM = MS ….(iv) [From (i), (ii) and (iii)] 

In ∆PMS, PM = MS [From (iv)] 

∴ ∠MSP = ∠MPS = x° …..(v) [Isosceles triangle theorem] 

∠PMS = ∠QMR = 50° ……(vi) [Vertically opposite angles] 

In ∆MPS, ∠PMS + ∠MPS + ∠MSP = 180° [Sum of the measures of the angles of a triangle is 180°] 

∴ 50° + x + x = 180° [From (v) and (vi)] 

∴ 50° + 2x = 180° 

∴ 2x= 180° - 50° 

∴ 2x = 130° 

∴ x = 130/2 = 65° 

∴ ∠MPS = 65° [From (v)]

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