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in Pythagoras Theorem by (47.6k points)
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In the adjoining figure, ∠QPR = 90° , seg PM ⊥ seg QR and Q – M – R, PM = 10, QM = 8, find QR.

1 Answer

+1 vote
by (46.9k points)
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Best answer

In ∆PQR, ∠QPR = 90° and [Given] 

seg PM ⊥ seg QR 

∴ PM2 = OM × MR [Theorem of geometric mean] 

∴ 102 = 8 × MR 

∴ MR = 100/8 

= 12.5 

Now, QR = QM + MR [Q – M – R] 

= 8 + 12.5 

∴ QR = 20.5 units

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