In ∆PQR, ∠Q = 90°, ∠P = θ
∴ ∠R = 90 – θ
ii. cos θ = sin(90 – θ)
iii. Let ∠P = θ = 30°
∴ ∠R = 90° – 30°
sin 30° = cos(90° – 30°) … [From (i) and (ii)]
sin 30° = cos 60°
iv. cos 30° = sin(90° – 30°) = sin 60°
∴ cos 30° = sin(90° – 30°) .,.[From (i) and (ii)]
∴ cos 30° = sin 60°