Use app×
Join Bloom Tuition
One on One Online Tuition
JEE MAIN 2025 Foundation Course
NEET 2025 Foundation Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
+1 vote
3.0k views
in Circle by (46.9k points)
closed by

In the adjoining figure, ray PQ touches the circle at point Q. PQ = 12, PR = 8, find PS and RS.

1 Answer

+1 vote
by (47.6k points)
selected by
 
Best answer

i. Ray PQ is a tangent to the circle at point Q and seg PS is the secant. [Given] 

∴ PR × PS = PQ2 [Tangent secant segments theorem]

∴ 8 × PS = 122 

∴ 8 × PS = 144 

∴ PS = 144/8

∴ PS = 18 units 

ii. Now, PS = PR + RS [P – R – S] 

∴ 18 = 8 + RS 

∴ RS = 18 – 8 

∴ RS = 10 units

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

...