Use app×
Join Bloom Tuition
One on One Online Tuition
JEE MAIN 2025 Foundation Course
NEET 2025 Foundation Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
0 votes
3.6k views
in Surface Area and Volume by (49.5k points)
closed by

The inner diameter of a well is 4.20 metre and its depth is 10 metre. Find the inner surface area of the well. Find the cost of plastering it from inside at the rate Rs 52 per sq.m.

1 Answer

+1 vote
by (48.8k points)
selected by
 
Best answer

Given: Inner diameter (d) = 4.2 m, 

To find: depth (h) = 10 m, rate of plastering = Rs 52 per sq.m. 

Inner surface area and total cost of plastering 

i. Inner curved surface area of the well = 2πrh 

= πdh … [∵ d = 2r]

\(\sqrt[22]{7}\) x 4.2 x 10

= \(\sqrt[22]{7}\) x 42

= 22 x 6 

= 132 sq.m. 

ii. Rate of plastering = Rs 52 per sq.m. 

∴ Total cost = Curved surface area x Rate of plastering 

= 132 x 52 = Rs 6864 

∴ The cost of plastering the well from inside is Rs 6864.

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

...