Use app×
Join Bloom Tuition
One on One Online Tuition
JEE MAIN 2025 Foundation Course
NEET 2025 Foundation Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
0 votes
4.0k views
in Circle by (47.6k points)
closed by

Chords AB and CD of a circle intersect inside the circle at point E. If AE = 5.6, EB = 10, CE = 8, find ED. 

(A) 7 

(B) 8 

(C) 11.2 

(D) 9

1 Answer

+1 vote
by (46.9k points)
selected by
 
Best answer

(A) 7

Chords AB and CD intersect internally at E. 

AE × EB = CE × ED [Theorem of internal division of chords]

∴ 5.6 × 10 = 8 × ED 

∴ ED = 7 units

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

...