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Chords AB and CD of a circle intersect inside the circle at point E. If AE = 5.6, EB = 10, CE = 8, find ED. 

(A) 7 

(B) 8 

(C) 11.2 

(D) 9

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(A) 7

Chords AB and CD intersect internally at E. 

AE × EB = CE × ED [Theorem of internal division of chords]

∴ 5.6 × 10 = 8 × ED 

∴ ED = 7 units

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