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The total remuneration paid to laborers, employed to harvest soybean is in direct variation with the number of laborers. If remuneration of 4 laborers is Rs 1000, find the remuneration of 17 laborers.

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Let, m represent total remuneration paid to laborers and n represent number of laborers employed to harvest soybean. 

Since, the total remuneration paid to laborers, is in direct variation with the number of laborers.

∴ m ∝ n 

∴ m = kn …(i)

where, k = constant of variation 

Remuneration of 4 laborers is Rs 1000. 

i. e., when n = 4, m = Rs 1000 

∴ Substituting, n = 4 and m = 1000 in (i), we get m = kn 

∴ 1000 = k × 4

∴ k = 1000/4

∴ k = 250 Substituting, k = 250 in (i), we get m = kn 

∴ m = 250 n …(ii) 

This is the equation of variation 

Now, we have to find remuneration of 17 laborers. 

i. e., when n = 17, m = ? 

∴ Substituting n = 17 in (ii), we get m = 250 n 

∴ m = 250 × 17 

∴ m = 4250 

∴ The remuneration of 17 laborers is Rs 4250.

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