i. Chords WX and YZ intersect internally at point T.
∴ ∠ZTX = 1/2 m(arc WY) + m(arc ZX)]
= 1/2 (44° + 68°)
= 1/2 × 112°
∴ m ∠ZTX = 56°
ii. WT × TX = YT × TZ [Theorem of internal division of chords]
∴ 4.8 × 8.0 = 6.4 × TZ
∴ TZ = (4.8 x 8.0) / 6.4
∴ l(TZ) = 6.0 units
iii. Let the value of WT be x. [W – T – X]
WT + TX = WX
∴ x + TX = 25
∴ TX = 25 – x
Also, YT + TZ = YZ [Y – T – Z]
∴ 8 + TZ = 26
∴ TZ = 26 – 8 = 18 units
But, WT × TX = YT × TZ [Theorem of internal division of chords]
∴ x × (25 – x) = 8 × 18
∴ 25x – x2 = 144
∴ x2 – 25x + 144 = 0
∴ (x – 16) (x – 9) = 0
∴ x = 16 or x = 9
∴ WT = 16 units or WT = 9 units