Sarthaks Test
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At 473 K, equilibrium constant Kc for decomposition of phosphorus pentachloride, PCl5 is 8.3 ×10–3 . If decomposition is depicted as, 

PCl5 (g) ⇌ PCl3(g) + Cl2(g) ΔrH0 = 124.0 kJ mol–1 

(a) Write an expression for Kc for the reaction. 

(b) What is the value of Kc for the reverse reaction at the same temperature? 

(c) What would be the effect on Kc if 

(i) more PCl5 is added 

(ii) pressure is increased 

(iii) the temperature is increased ? 

1 Answer

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Best answer

(a) Kc=[PCl3] [Cl2] / [PCl5]

(b) 120.48 

(c) (i) equilibrium will shift on RHS. 

(ii) equilibrium will shift on LHS. 

(iii) equilibrium will shift on RHS.

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