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in Co-ordinate Geometry by (46.9k points)
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Find the point on X-axis which is equidistant from P (2, -5) and Q (-2,9)

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Let point R be on the X-axis which is equidistant from points P and Q. 

Point R lies on X-axis. 

∴ its y co-ordinate is 0. 

Let R = (x, 0) R is equidistant from points P and Q. 

∴ PR = QR

\(\sqrt {(x - 2)^2 + [0 - (-5)]^2}\)  ....[By distance formula] 

\(\sqrt {[x- (-2)]^2 + (0 - 9)^2}\) 

∴ (x – 2)2 + [0 – (-5)]2 = [x – (- 2)]2 + (0 – 9)2 …[Squaring both sides] 

∴ (x – 2)2 + (5)2 = (x + 2)2 + (-9)2

∴ 4 – 4x + x2 + 25 = 4 + 4x + x2 + 81 

∴ – 8x = 56 

∴ x = -7 

∴ The point on X-axis which is equidistant form points P and Q is (-7, 0).

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