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Find the co-ordinates of centroid of the triangle if points D (-7, 6), E (8, 5) and F (2, -2) are the mid points of the sides of that triangle.

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Suppose A (x1 , y1 ), B (x2 , y2 ) and C (x3 , y3 ) are the vertices of the triangle. 

D (-7, 6), E (8, 5) and F (2, -2) are the midpoints of sides BC, AC and AB respectively.

Let G be the centroid of ∆ABC. 

D is the midpoint of seg BC. 

By midpoint formula,

E is the midpoint of seg AC. 

By midpoint formula,

Adding (i), (iii) and (v), x2 + x3 + x1 + x3 + x1 + x2 = -14 + 16 + 4 

∴ 2x1 + 2x2 + 2x3 = 6 

∴ x1 + x2 + x3 = 3 …(vii) Adding (ii), (iv) and (vi),

y2 + y3 + y1 + y3 + y1 +y2 = 12 + 10 – 4 

∴ 2y1 + 2y2 + 2y3 = 18 

∴ y1 + y2 + y3 = 9 …(viii) 

G is the centroid of ∆ABC. 

By centroid formula,

∴ The co-ordinates of the centroid of the triangle are (1,3).

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