Suppose A (x1 , y1 ), B (x2 , y2 ) and C (x3 , y3 ) are the vertices of the triangle.
D (-7, 6), E (8, 5) and F (2, -2) are the midpoints of sides BC, AC and AB respectively.
Let G be the centroid of ∆ABC.
D is the midpoint of seg BC.
By midpoint formula,
E is the midpoint of seg AC.
By midpoint formula,
Adding (i), (iii) and (v), x2 + x3 + x1 + x3 + x1 + x2 = -14 + 16 + 4
∴ 2x1 + 2x2 + 2x3 = 6
∴ x1 + x2 + x3 = 3 …(vii) Adding (ii), (iv) and (vi),
y2 + y3 + y1 + y3 + y1 +y2 = 12 + 10 – 4
∴ 2y1 + 2y2 + 2y3 = 18
∴ y1 + y2 + y3 = 9 …(viii)
G is the centroid of ∆ABC.
By centroid formula,
∴ The co-ordinates of the centroid of the triangle are (1,3).