Question

Show that A (4, -1), B (6, 0), C (7, -2) and D (5, -3) are vertices of a square.

Answer 1

Proof: 

By distance formula,

                      = \(\sqrt {3^2 +(-2 + 1)^2}\)

∴ □ABCD is a square. [A rhombus is a square if its diagonals are equal]

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