Question

A particle performs harmonic oscillations along the x-axis about the equilibrium position x = 0. The oscillation frequency is ω = 4.00s^-1 At a certain moment of time the particle has a coordinate x_o = 25.0cm and its velocity is equal to v_x0 = 100cm/s.

Find the coordinate x and the velocity vs of the particle t = 2.40s after that moment.

Answer 1

Let the general equation of S.H.M. be

 

Let us assume that at t = 0, x = x₀ and v_x = v_x0.

 

 

Under our assumption eqns (1) and (2) given the sought x and v_x if

Putting all the given numerical values, we get:

Comments

how is  a = { (x^2) + (velocity/angular frequency)^2}^1/2