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In a parallelogram ABCD, if ∠DAB = 75°, ∠DBC = 60° then find ∠CDB.

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In ||gm, ∠DCB = ∠DAB = 75° 

(Opposite angles of parallelogram are equal) 

In ∆DCB, ∠DBC + ∠DCB + ∠CDB = 180°

60° + 75° + ∠CDB = 180° 

∠CDB = 180 ° – 135° = 45° 

∠CDB = 45°

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