From the motion law, x = acosωt,it is obvious that the time taken to cover the distance equal to the amplitude (a), starting from extreme position equal T/4.
Now one can write
As the particle moves according to the law, x = acosωt,
so at n = 1,3,5.... or for odd n values it passes through the mean position and for even numbers of n it comes to an extreme position(if t0 = o).
case (1) when n is an odd number :
in this case, from the equation
x = ± asinωt, if the t is counted from nT/4 and the distance covered in the time interval to becomes,s1 = asinωt0 = a sinω(t - n(T/4)) = asin(ωt - nπ/2)
Thus the sought distance covered for odd n is
Case (2), When n is even, in this case from the equation
x = acosωt,the distance covered (s2) in the interval t0, is given by
Hence the sought distance for n is even