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in Trigonometry by (47.6k points)
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Prove the following:

i. (tan3θ - 1)/(tanθ - 1) = sec2θ + tanθ

ii. (sinθ - cosθ + 1)/(sinθ + cosθ - 1) = 1/ (secθ - tanθ)

1 Answer

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Best answer

ii. We know that, 

sin2 θ + cos2 θ = 1 

∴ 1 – sin θ = cos θ 

∴ (1 – sin θ) (1 + sin θ) = cos θ. cos θ

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