Let AB and CD represent the heights of the two buildings, and BD represent the width of the road.
Draw seg AM ⊥ seg CD
Angle of elevation = ∠CAM = 30°
AB = 12m
BD = 15m
In \(\Box\)ABDM,
∠B = ∠D = 90°
∠M 90° …[segAM ⊥ segCD]
∠A 90° …[Remaining angle of \(\Box\)ABDM]
\(\Box\)ABDM is a rectangle …[Each angle is 90°]
∴ The height of the second building is 20.65 m.