Given: Radius (r) =15 cm, central angle (θ) = 60°
To find: Areas of major and minor segments.
Let chord PQ subtend ∠POQ = 60° at centre.
∴ θ = 60°
= 225 [0.0908]
= 20.43 cm2
∴ area of minor segment = 20.43 cm2
Area of circle = πr2
= 3.14 × 15 × 15
= 3.14 × 225
= 706.5 cm2
Area of major segment = Area of circle – area of minor segment
= 706.5 – 20.43
= 686.07 cm2
Area of major segment 686.07 cm2
∴ The area of minor segment Is 20.43 cm2 and the area of major segment is 686.07 cm2 .