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in Algebraic Expressions and Operations on them by (46.9k points)
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i. 17a²b² + 16c; 28c – 28a²b² 

ii. 3y² – 10y + 16; 2y – 7 

iii. – 3y² + 10y – 16; 7y² + 8

1 Answer

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Best answer

i. (17a²b² + 16c) + (28c – 28a²b²) 

= [17a²b² + (-28a²b²)] + (16c + 28c) 

= -11a²b² + 44c 

ii. (3y² – 10y + 16) + (2y – 7) 

= 3y² + (-10y + 2y) + (16 – 7) 

= 3y² – 8y + 9 

iii. (-3y² + 10y – 16) + (7y² + 8) 

= (-3y² + 7y²) + (10y) + (-16 + 8) 

= 4y² + 10y – 8

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