Use app×
Join Bloom Tuition
One on One Online Tuition
JEE MAIN 2025 Foundation Course
NEET 2025 Foundation Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
0 votes
3.3k views
in Algebraic Expressions and Operations on them by (46.9k points)
closed by

Subtract the second expression from the first.

i. (6x² + 7xy + 16y²); (16x² – 17xy) 

ii. (4x + 16z); (19y – 14z + 16x)

1 Answer

+1 vote
by (47.6k points)
selected by
 
Best answer

iv. (6x² + 7xy + 16y²) – (16x² – 17xy) 

= 6x² + 7xy + 16y² – 16x² + 17xy 

= (6x² – 16x²) + (7xy + 17xy) + 16y² 

= -10x² + 24xy + 16y2

v. (4x + 16z) – (19y - 14z + 16x) 

= 4x + 16z – 19y + 14z – 16x 

= (4x – 16x) – 19y + (16z + 14z) 

= -12x – 19y + 30z

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

...