(a) Let us differentiate twice the path equation y(x) with respect to time.
Since the particle moves uniformly, its acceleration at all point of the path is normal and at the point x=0 it coincides with the direction of derivative d2y/dt2. Keeping in mind
(b) Differentiating the equation of the trajectory with respect to time we see that
is normal to the velocity vector
which, of course, is along the tangent. Thus the former vector is along the normal and the normal component of acceleration is clearly