Use app×
Join Bloom Tuition
One on One Online Tuition
JEE MAIN 2025 Foundation Course
NEET 2025 Foundation Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
0 votes
887 views
in Perimeter and Area by (46.9k points)
closed by

Is there another way to find the area of the pathway in the problem above?

1 Answer

+1 vote
by (47.6k points)
selected by
 
Best answer

Yes. The area of the pathway can be found by dividing it into rectangles and adding the areas of these rectangles. 

Length of rectangle 1 = 30 + 1.5 + 1.5 

= 33 m 

Breadth of rectangle 1 = 1.5 m 

∴ Area of rectangle 1 = 33 x 1.5 

= 49.5 sq.m 

Area of rectangle 4 = Area of rectangle 1 

= 49.5 sq. m. 

Length of rectangle 2 = 65 m 

breadth of rectangle 2 = 1.5 m 

∴ Area of rectangle 2 = 65 x 1.5 

= 97.5 sq. m. 

Area of rectangle 3 = area of rectangle 2 

= 97.5 sq. m. 

∴ Area of pathway = Sum of area of the 4 rectangles = 49.5 + 49.5 + 97.5 + 97.5 

= 294 sq. m.

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

...