LIVE Course for free

Rated by 1 million+ students
Get app now
+1 vote
by (29.8k points)

Nitric oxide reacts with Br2 and gives nitrosyl bromide as per reaction given below: 

When 0.087 mol of NO and 0.0437 mol of Br2 are mixed in a closed container at constant temperature, 0.0518 mol of NOBr is obtained at equilibrium. Calculate equilibrium amount of NO and Br2

1 Answer

+1 vote
by (128k points)
selected by
Best answer

The given reaction is: 

Now, 2 mol of NOBr are formed from 2 mol of NO. Therefore, 0.0518 mol of NOBr are formed from 0.0518 mol of NO. 

Again, 2 mol of NOBr are formed from 1 mol of Br. 

Therefore, 0.0518 mol of NOBr are formed from mol of Br, or 0.0259 mol of NO. 

The amount of NO and Br present initially is as follows: 

[NO] = 0.087 mol [Br2] = 0.0437 mol 

Therefore, the amount of NO present at equilibrium is: 

[NO] = 0.087 – 0.0518 = 0.0352 mol 

And, the amount of Br present at equilibrium is: 

[Br2] = 0.0437 – 0.0259 = 0.0178 mol 

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.